If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3p^2=20-11p
We move all terms to the left:
3p^2-(20-11p)=0
We add all the numbers together, and all the variables
3p^2-(-11p+20)=0
We get rid of parentheses
3p^2+11p-20=0
a = 3; b = 11; c = -20;
Δ = b2-4ac
Δ = 112-4·3·(-20)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-19}{2*3}=\frac{-30}{6} =-5 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+19}{2*3}=\frac{8}{6} =1+1/3 $
| -3=n-4/2 | | x-63=46 | | -9=-6+n/2 | | -8n+4+20n=6n-4 | | 0=3m-3m-7 | | 7(1+7m)=252 | | 4=(x=2)/(-3) | | 1x+2=7x-3 | | 3x12=9 | | 4+r=11 | | 5x-6+x=180 | | 3y-24=18 | | p+10=1 | | x-13=97 | | -8+4(1+5n)=6n-4 | | 9+3r-4=8r+15-3r | | -4(1-3x)=26+12x | | -5=m-3 | | X+2y=2820 | | n/3=5/3 | | 5y+3+2y+9=8y-9 | | (8x+9)=(5x-9) | | -4(1-3x=26+12x | | x+9x-(6x+4x)=20 | | 5/2x+1=16 | | 70=-10n | | 5/2x=1=16 | | x+3.75=11/13 | | 4(2y-1)-2y+4=12 | | -4u-36=4(u+9) | | 3(5y+1)=18 | | 5/6x+29=1/6×+31 |